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Proof step 3 from proof abs-orphans-diff-datakeys (previous step)

⊦ ∀ ino0. ino0 ∈ orphans(abs-dirs(fs, ri), abs-files(fs, ri \ datakeys(inodekey(ino), n, ri))) ↔ ino0 ∈ orphans(abs-dirs(fs, ri), abs-files(fs, ri))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information