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Proof step 29 from proof dups-eqsize-ls (previous step)

∀ key0. key0 ∈ ks0 → key0.dentry?, ∀ key. key.dentry? → (key = dentrykey(m, str) ∨ key ∈ ks0 ↔ mklink(key.ino, key.name) = mklink(m, str) ∨ mklink(key.ino, key.name) ∈ ls0), ∀ ls1, ks. # ls1 < #(ls0 ++ mklink(m, str)) → (∀ key. key ∈ ks → key.dentry?) ∧ (∀ key. key.dentry? → (key ∈ ks ↔ mklink(key.ino, key.name) ∈ ls1)) → # ks = # ls1 ⊦ # ks0 = # ls0, dentrykey(m, str) ∈ ks0, mklink(m, str) ∈ ls0

User applied rule apply induction

And obtained the following new goals

Proof step 30:
∀ key. key.dentry? → (key = dentrykey(m, str) ∨ key ∈ ks0 ↔ mklink(key.ino, key.name) = mklink(m, str) ∨ mklink(key.ino, key.name) ∈ ls0), ∀ key0. key0 ∈ ks0 → key0.dentry?, ∀ ls1, ks. # ls1 < #(ls0 ++ mklink(m, str)) → (∀ key. key ∈ ks → key.dentry?) ∧ (∀ key. key.dentry? → (key ∈ ks ↔ mklink(key.ino, key.name) ∈ ls1)) → # ks = # ls1 ⊦ # ks0 = # ls0, mklink(m, str) ∈ ls0, dentrykey(m, str) ∈ ks0, (∀ key. key ∈ ks0 → key.dentry?) ∧ (∀ key. key.dentry? → (key ∈ ks0 ↔ mklink(key.ino, key.name) ∈ ls0))

Rule argument

subst: [ls1, ks] → [ls0, ks0]

Additional information

Used simplifier rules: ⊦ ¬ alink ∈ ls → #(ls ++ alink) = # ls + 1; (s)% ⊦ m < n + 1 ↔ ¬ n < m; (s)% ⊦ ¬ n < n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used terms: ls0, ks0