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Proof step 1 from proof elim-dentry (conclusion)

⊦ key.dentry? ↔ (∃ ino, str. key = dentrykey(ino, str))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
key.dentry? ⊦ ∃ ino, str. key = dentrykey(ino, str)

Rule argument

Additional information

Used simplifier rules: ⊦ dentrykey(m, str).dentry?; (s)