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Proof step 1 from proof elim-inode (conclusion)

⊦ key.inode? ↔ (∃ ino. key = inodekey(ino))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
key.inode? ⊦ ∃ ino. key = inodekey(ino)

Rule argument

Additional information

Used simplifier rules: ⊦ inodekey(m).inode?; (s)