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Proof step 83 from proof inv-create (previous step)

fs1[ri1[datakey(ino, n0)]] = datanode(datakey(ino, n0), buf), fs1[ri1[inodekey(m)]].directory, (adr3 = ri1[inodekey(ino)] ⊃ inodenode(inodekey(n), md, false, 1, 0, 0) ;(adr2 = ri1[inodekey(ino)] ⊃ dentrynode(dentrykey(m, str), n) ;(adr1 = ri1[inodekey(ino)] ⊃ inodenode(inodekey(m), md0, true, fs1[ri1[inodekey(m)]].nlink, fs1[ri1[inodekey(m)]].nsubdirs, fs1[ri1[inodekey(m)]].size + 1) ;fs1[ri1[inodekey(ino)]] ) ) ) .directory, fs1[ri1[inodekey(m)]].inode?, fo.inodes?, ro.inodes?, file-node-cons(fs1, ri1), log-cons(log0, fs1), orphans-cons(fs1, ri1, ro), replay-cons-strong(fs1, ri1, ro, fi, fo, log0), ri-inj(fi), ri-inj(ri1), ubifs-cons(fs1, ri1, ro, fi, fo, log0), ri1[datakey(ino, n0)] ∈ fs1, ri1[inodekey(m)] ∈ fs1, inodekey(m) ∈ ri1, datakey(ino, n0) ∈ ri1, inodekey(ino) ∈ ri1, fs1[ri1[inodekey(m)]].nlink ≠ 0 ∨ m = ROOT_INO ⊦ 0 = m, adr1 = adr3, adr1 = adr2, adr2 = adr3, adr3 = ri1[inodekey(ino)], ino = 0, n = 0, fs1[ri1[inodekey(ino)]].directory, inodekey(m) ∈ ro, dentrykey(m, str) ∈ ri1, inodekey(n) ∈ fo, inodekey(n) ∈ ri1, adr1 ∈ fs1, adr2 ∈ fs1, adr3 ∈ fs1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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