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Proof step 52 from proof inv-format (previous step)

⊦ ( ¬ inodekey(0) ∈ (∅)[inodekey(ROOT_INO), adr1] ∧ ri-cons((∅)[inodekey(ROOT_INO), adr1], (∅)[adr1, inodenode(inodekey(ROOT_INO), md, true, 0, 0, 0)]) ∧ log-cons(adr1 ', (∅)[adr1, inodenode(inodekey(ROOT_INO), md, true, 0, 0, 0)]) ∧ ¬ dups(adr1 ') ∧ ri-closed((∅)[inodekey(ROOT_INO), adr1], (∅)[adr1, inodenode(inodekey(ROOT_INO), md, true, 0, 0, 0)], ∅) ∧ ∅.inodes? ∧ ∅.inodes? ∧ ∅ ⊆ dom (∅)[inodekey(ROOT_INO), adr1] ∧ ∅ ⊆ dom ∅) ∧ replay-cons-strong((∅)[adr1, inodenode(inodekey(ROOT_INO), md, true, 0, 0, 0)], (∅)[inodekey(ROOT_INO), adr1], ∅, ∅, ∅, adr1 ') ∧ file-node-cons((∅)[adr1, inodenode(inodekey(ROOT_INO), md, true, 0, 0, 0)], (∅)[inodekey(ROOT_INO), adr1]) ∧ orphans-cons((∅)[adr1, inodenode(inodekey(ROOT_INO), md, true, 0, 0, 0)], (∅)[inodekey(ROOT_INO), adr1], ∅)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: in-ri: ⊦ key0 ∈ ri[key1, adr] ↔ key0 = key1 ∨ key0 ∈ ri;%at-fs: ⊦ fs[adr0, nd][adr1] = (adr0 = adr1 ⊃ nd;fs[adr1]);% ⊦ ∅ ⊆ ks; (s)% ⊦ dom ∅ = ∅; (s)% ⊦ dom ri[key, adr] = dom ri ++ key; (s)% ⊦ ∅.inodes?; (s)% ⊦ ¬ dups(adr '); (s)% ⊦ inodekey(m).ino = m; (s)% ⊦ inodekey(m).inode?; (s)%⊦ node-cons(key0, inodenode(key1, md, boolvar, n, n0, m)) ↔ key0.inode? ∧ key0.ino ≠ 0; (s)% ⊦ inodenode(key, md, boolvar, m, m0, m1).key = key; (s)% ⊦ adr ∈ fs[adr1, nd] ↔ adr = adr1 ∨ adr ∈ fs; (s)% ⊦ log-cons(adr ', fs) ↔ adr ∈ fs ∧ node-cons(fs[adr].key, fs[adr]); (s)% ⊦ ¬ key ∈ ∅; (s)% ⊦ ROOT_INO ≠ 0; (s)% ⊦ inodekey(m) = inodekey(m0) ↔ m = m0; (s)