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Proof step 156 from proof inv-link (previous step)

fs[ri[dentrykey(ino, str)]].ino = fs[ri[dentrykey(ino0, str)]].ino, fs[ri[dentrykey(ino0, str)]].dentry?, fs[ri[inodekey(ino)]].directory, fs[ri[inodekey(m3)]].directory, fs[ri[inodekey(ino0)]].directory, fo.inodes?, ro.inodes?, file-node-cons(fs, ri), log-cons(log, fs), orphans-cons(fs, ri, ro), replay-cons-strong(fs, ri, ro, fi, fo, log), ri-cons(ri, fs), ri-inj(fi), ri-inj(ri), ubifs-cons(fs, ri, ro, fi, fo, log), inodekey(ino0) ∈ ri, dentrykey(ino, str) ∈ ri, inodekey(ino) ∈ ri, ri[dentrykey(ino0, str)] ∈ fs, inodekey(fs[ri[dentrykey(ino0, str)]].ino) ∈ ri, inodekey(m3) ∈ ri, dentrykey(ino0, str) ∈ ri, ⌊err0⌋ , fs[ri[inodekey(ino)]].nlink ≠ 0 ∨ ino = ROOT_INO, fs[ri[inodekey(m3)]].nlink ≠ 0 ∨ m3 = ROOT_INO, fs[ri[inodekey(ino0)]].nlink ≠ 0 ∨ ino0 = ROOT_INO ⊦ ⟪skip⟫ (ubifs-cons(fs, ri, ro, fi, fo, log) ∧ replay-cons-strong(fs, ri, ro, fi, fo, log) ∧ file-node-cons(fs, ri) ∧ orphans-cons(fs, ri, ro)), fs[ri[dentrykey(ino0, str)]].ino = 0, m3 = 0, fs[ri[inodekey(fs[ri[dentrykey(ino0, str)]].ino)]].directory, inodekey(ino) ∈ ro, inodekey(fs[ri[dentrykey(ino0, str)]].ino) ∈ ro, dentrykey(m3, str0) ∈ ri, inodekey(m3) ∈ ro, inodekey(ino0) ∈ ro

Heuristic symbolic execution applied rule skip right

And closed the goal!

Rule argument

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