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Proof step 168 from proof inv-link (previous step)

fs[ri[dentrykey(ino, str)]].dentry?, fs[ri[inodekey(ino)]].directory, fs[ri[inodekey(m)]].directory, ro.inodes?, fo.inodes?, file-node-cons(fs, ri), log-cons(log, fs), orphans-cons(fs, ri, ro), replay-cons-strong(fs, ri, ro, fi, fo, log), ri-inj(ri), ri-inj(fi), ubifs-cons(fs, ri, ro, fi, fo, log), dentrykey(ino, str) ∈ ri, inodekey(m) ∈ ri, inodekey(fs[ri[dentrykey(ino, str)]].ino) ∈ ri, inodekey(ino) ∈ ri, ri[dentrykey(ino, str)] ∈ fs, fs[ri[inodekey(m)]].nlink ≠ 0 ∨ m = ROOT_INO ⊦ fs[ri[inodekey(ino)]].nlink = 0, fs[ri[inodekey(fs[ri[dentrykey(ino, str)]].ino)]].directory, inodekey(ino) ∈ ro, inodekey(m) ∈ ro, dentrykey(m, str0) ∈ ri, inodekey(fs[ri[dentrykey(ino, str)]].ino) ∈ ro, ∃ ino0. inodekey(ino0) ∈ ri ∧ (fs[ri[inodekey(ino0)]].nlink ≠ 0 ∨ ino0 = ROOT_INO) ∧ ¬ inodekey(ino0) ∈ ro ∧ dentrykey(ino0, str) ∈ ri ∧ fs[ri[dentrykey(ino0, str)]].ino = fs[ri[dentrykey(ino, str)]].ino

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 7 terms: ino

Additional information

Used terms: ino