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Proof step 125 from proof inv-mkdir (previous step)

fs1[ri1[inodekey(ino)]].nlink = 0 ↔ inodekey(ino) ∈ ro, fs1[ri1[inodekey(m)]] = inodenode(key, md1, true, m0, m1, m2), fo.inodes?, ro.inodes?, file-node-cons(fs1, ri1), log-cons(log0, fs1), orphans-cons(fs1, ri1, ro), replay-cons-strong(fs1, ri1, ro, fi, fo, log0), ri-inj(fi), ri-inj(ri1), ubifs-cons(fs1, ri1, ro, fi, fo, log0), ri1[inodekey(m)] ∈ fs1, inodekey(m) ∈ ri1, inodekey(ino) ∈ ri1, m0 ≠ 0 ∨ m = ROOT_INO ⊦ (adr3 = (m = ino ⊃ adr1;ri1[inodekey(ino)]) ⊃ inodenode(inodekey(n), md, true, 1, 0, 0) ;(adr2 = (m = ino ⊃ adr1;ri1[inodekey(ino)]) ⊃ dentrynode(dentrykey(m, str), n) ;(adr1 = (m = ino ⊃ adr1;ri1[inodekey(ino)]) ⊃ inodenode(inodekey(m), md0, true, m0, m1 + 1, m2 + 1);fs1[(m = ino ⊃ adr1;ri1[inodekey(ino)])]) ) ) .nlink = 0 ↔ inodekey(ino) ∈ ro, adr1 = adr3, adr1 = adr2, adr2 = adr3, adr3 = (m = ino ⊃ adr1;ri1[inodekey(ino)]), ino = ROOT_INO, n = 0, inodekey(m) ∈ ro, dentrykey(m, str) ∈ ri1, inodekey(n) ∈ fo, inodekey(n) ∈ ri1, adr1 ∈ fs1, adr2 ∈ fs1, adr3 ∈ fs1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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