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Proof step 193 from proof inv-rename-new-keep-parent (previous step)

boolvar0 ↔ boolvar2, boolvar ↔ boolvar1, new_dent = negdentry(str0), old_child_inode = mkinode(fs[ri[dentrykey(m, str)]].ino, md0, boolvar2, m1, m2, m3), old_dent = mkdentry(str, fs[ri[dentrykey(m, str)]].ino), parent_inode = mkinode(m, md, true, fs[ri[inodekey(m)]].nlink, fs[ri[inodekey(m)]].nsubdirs, fs[ri[inodekey(m)]].size), fs[ri[dentrykey(m, str)]].dentry?, fs[ri[inodekey(m)]].directory, ro.inodes?, fo.inodes?, file-node-cons(fs, ri), log-cons(log, fs), orphans-cons(fs, ri, ro), replay-cons-strong(fs, ri, ro, fi, fo, log), ri-inj(ri), ri-inj(fi), ubifs-cons(fs, ri, ro, fi, fo, log), ri[dentrykey(m, str)] ∈ fs, inodekey(m) ∈ ri, inodekey(fs[ri[dentrykey(m, str)]].ino) ∈ ri, dentrykey(m, str) ∈ ri, 1 ≤ fs[ri[inodekey(m)]].size, boolvar2 → 1 ≤ fs[ri[inodekey(m)]].nsubdirs, ¬ fs[ri[inodekey(fs[ri[dentrykey(m, str)]].ino)]].directory ∧ ¬ boolvar2 ∧ m1 = fs[ri[inodekey(fs[ri[dentrykey(m, str)]].ino)]].nlink ∧ m2 = fs[ri[inodekey(fs[ri[dentrykey(m, str)]].ino)]].nsubdirs ∨ fs[ri[inodekey(fs[ri[dentrykey(m, str)]].ino)]].directory ∧ boolvar2 ∧ m1 = fs[ri[inodekey(fs[ri[dentrykey(m, str)]].ino)]].nlink ∧ m2 = fs[ri[inodekey(fs[ri[dentrykey(m, str)]].ino)]].nsubdirs ∧ m3 = fs[ri[inodekey(fs[ri[dentrykey(m, str)]].ino)]].size, fs[ri[inodekey(m)]].nlink ≠ 0 ∨ m = ROOT_INO ⊦ fs[ri[inodekey(m)]].size = 0, inodekey(m) ∈ ro, dentrykey(m, str0) ∈ ri, ∃ key1, key0, key, nd1, nd0, nd, adr1, adr0, adr. true

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

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