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Proof step 164 from proof inv-rename-new-reparent (previous step)

fs0[ri0[dentrykey(m, str)]] = dentrynode(key1, m3), fs0[ri0[inodekey(m3)]] = inodenode(key0, md1, boolvar0, m5, m9, m10), fs0[ri0[inodekey(m0)]] = inodenode(key2, md3, true, m6, m7, m8), replay-log(log0, fs0, fi ⊖ fo) = ri0 ⊖ ro, fo.inodes?, ro.inodes?, file-node-cons(fs0, ri0), log-cons(log0, fs0), orphans-cons(fs0, ri0, ro), replay-cons-strong(fs0, ri0, ro, fi, fo, log0), replay-safe(log0, fs0, fi ⊖ fo), ri-inj(fi), ri-inj(ri0), ubifs-cons(fs0, ri0, ro, fi, fo, log0), dentrykey(m, str) ∈ ri0, inodekey(m3) ∈ ri0, inodekey(m0) ∈ ri0, ri0[dentrykey(m, str)] ∈ fs0, ri0[inodekey(m3)] ∈ fs0, inodekey(m) ∈ ri0, ri0[inodekey(m0)] ∈ fs0, ri0[inodekey(m)] ∈ fs0, m2 ≠ 0 ∨ m = ROOT_INO, m6 ≠ 0 ∨ m0 = ROOT_INO, ¬ boolvar0 ∧ ¬ boolvar2 ∨ boolvar0 ∧ boolvar2 ∧ m4 = m10, key = dentrykey(m0, str0) ∨ key ∈ ri0 ⊖ ro ⊦ adr1 = adr4, adr1 = adr3, adr1 = adr2, adr2 = adr4, adr2 = adr3, adr3 = adr4, key = inodekey(m), key = inodekey(m0), key = dentrykey(m, str), m = 0, m0 = m, m0 = 0, m3 = 0, adr3 ∈ (ri0 -- dentrykey(m, str))[dentrykey(m0, str0), adr2], inodekey(m) ∈ ro, dentrykey(m0, str0) ∈ ri0, inodekey(m0) ∈ ro, adr1 ∈ fs0, adr2 ∈ fs0, adr3 ∈ fs0, adr4 ∈ fs0, adr2 ∈ ri0 -- dentrykey(m, str), adr4 ∈ (ri0 -- dentrykey(m, str))[dentrykey(m0, str0), adr2][inodekey(m), adr3], adr4 ∈ log0, adr3 ∈ log0, adr2 ∈ log0, adr1 ∈ log0, (key = dentrykey(m0, str0) ∨ key ∈ ri0) ∧ ¬ key ∈ ro ∧ (key.data? → ¬ inodekey(key.ino) ∈ ro)

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: key = dentrykey(m0, str0)

Additional information

Used simplifier rules: ⊦ key ∈ ri ⊖ ks ↔ key ∈ ri ∧ ¬ key ∈ ks ∧ (key.data? → ¬ inodekey(key.ino) ∈ ks); (ws)% ⊦ inodekey(m) ≠ dentrykey(m0, str); (s)% ⊦ ks.inodes? → ¬ dentrykey(ino, str) ∈ ks; (s)% ⊦ ¬ dentrykey(m, str).data?; (s) Used formulas: key = dentrykey(m0, str0)