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Proof step 274 from proof inv-rename-overwrite-keep-parent (previous step)

¬ boolvar1 ↔ ¬ boolvar0, fs0[ri0[dentrykey(m, str0)]] = dentrynode(key4, m1), fs0[ri0[dentrykey(m, str)]] = dentrynode(key0, m2), fs0[ri0[inodekey(m2)]] = inodenode(key1, md0, boolvar0, m5, m9, m10), fs0[ri0[inodekey(m1)]] = inodenode(key3, md3, boolvar1, 1, m11, m12), links(m1, fs0, ri0) = ∅ ++ dentrykey(m, str0), fo.inodes?, ro.inodes?, file-node-cons(fs0, ri0), log-cons(log0, fs0), orphans-cons(fs0, ri0, ro), replay-cons-strong(fs0, ri0, ro, fi, fo, log0), ri-cons(ri0, fs0), ri-inj(fi), ri-inj(ri0), ubifs-cons(fs0, ri0, ro, fi, fo, log0), dentrykey(m, str) ∈ ri0, inodekey(m2) ∈ ri0, dentrykey(m, str0) ∈ ri0, inodekey(m1) ∈ ri0, ri0[dentrykey(m, str)] ∈ fs0, ri0[inodekey(m2)] ∈ fs0, inodekey(m) ∈ ri0, ri0[dentrykey(m, str0)] ∈ fs0, ri0[inodekey(m1)] ∈ fs0, ri0[inodekey(m)] ∈ fs0, inodekey(ino) ∈ ri0, boolvar1 → dentrykeys(inodekey(m1), ri0) = ∅, ¬ fs0[ri0[inodekey(ino)]].directory → fs0[ri0[inodekey(ino)]].nsubdirs = 0, m4 ≠ 0 ∨ m = ROOT_INO, ¬ boolvar0 ∧ ¬ boolvar3 ∨ boolvar0 ∧ boolvar3 ∧ m3 = m10, ¬ boolvar0 ∧ ¬ boolvar2 ∨ boolvar1 ∧ boolvar2 ∧ m6 = m12 ⊦ (adr3 = ri0[inodekey(ino)] ⊃ inodenode(inodekey(m), md, true, m4, n0, m0) ;(adr2 = ri0[inodekey(ino)] ⊃ dentrynode(dentrykey(m, str0), m2) ;(adr1 = ri0[inodekey(ino)] ⊃ dentrynode(dentrykey(m, str), 0);fs0[ri0[inodekey(ino)]]) ) ) .nsubdirs = 0, adr1 = adr4, adr1 = adr3, adr1 = adr2, adr2 = adr4, adr2 = adr3, adr3 = adr4, adr4 = ri0[inodekey(ino)], m = ino, m = 0, m1 = ino, m1 = 0, m1 = ROOT_INO, mkdentry(str, m2) = mkdentry(str0, m1), (adr3 = ri0[inodekey(ino)] ⊃ inodenode(inodekey(m), md, true, m4, n0, m0) ;(adr2 = ri0[inodekey(ino)] ⊃ dentrynode(dentrykey(m, str0), m2) ;(adr1 = ri0[inodekey(ino)] ⊃ dentrynode(dentrykey(m, str), 0);fs0[ri0[inodekey(ino)]]) ) ) .directory, adr3 ∈ (ri0 -- dentrykey(m, str))[dentrykey(m, str0), adr2], inodekey(m) ∈ ro, adr1 ∈ fs0, adr2 ∈ fs0, adr3 ∈ fs0, adr4 ∈ fs0, adr2 ∈ ri0 -- dentrykey(m, str), adr4 ∈ (ri0 -- dentrykey(m, str))[dentrykey(m, str0), adr2][inodekey(m), adr3]

Heuristic nonsplitting cut applied rule cut formula

And obtained the following new goals

Proof step 275:
¬ boolvar1 ↔ ¬ boolvar0, fs0[ri0[inodekey(m1)]] = inodenode(key3, md3, boolvar1, 1, m11, m12), fs0[ri0[inodekey(m2)]] = inodenode(key1, md0, boolvar0, m5, m9, m10), fs0[ri0[dentrykey(m, str)]] = dentrynode(key0, m2), fs0[ri0[dentrykey(m, str0)]] = dentrynode(key4, m1), links(m1, fs0, ri0) = ∅ ++ dentrykey(m, str0), ro.inodes?, fo.inodes?, file-node-cons(fs0, ri0), log-cons(log0, fs0), orphans-cons(fs0, ri0, ro), replay-cons-strong(fs0, ri0, ro, fi, fo, log0), ri-cons(ri0, fs0), ri-inj(ri0), ri-inj(fi), ubifs-cons(fs0, ri0, ro, fi, fo, log0), inodekey(ino) ∈ ri0, ri0[inodekey(m)] ∈ fs0, ri0[inodekey(m1)] ∈ fs0, ri0[dentrykey(m, str0)] ∈ fs0, inodekey(m) ∈ ri0, ri0[inodekey(m2)] ∈ fs0, ri0[dentrykey(m, str)] ∈ fs0, inodekey(m1) ∈ ri0, dentrykey(m, str0) ∈ ri0, inodekey(m2) ∈ ri0, dentrykey(m, str) ∈ ri0, ¬ fs0[ri0[inodekey(ino)]].directory → fs0[ri0[inodekey(ino)]].nsubdirs = 0, boolvar1 → dentrykeys(inodekey(m1), ri0) = ∅, ¬ boolvar0 ∧ ¬ boolvar2 ∨ boolvar1 ∧ boolvar2 ∧ m6 = m12, ¬ boolvar0 ∧ ¬ boolvar3 ∨ boolvar0 ∧ boolvar3 ∧ m3 = m10, m4 ≠ 0 ∨ m = ROOT_INO ⊦ (adr3 = ri0[inodekey(ino)] ⊃ inodenode(inodekey(m), md, true, m4, n0, m0) ;(adr2 = ri0[inodekey(ino)] ⊃ dentrynode(dentrykey(m, str0), m2) ;(adr1 = ri0[inodekey(ino)] ⊃ dentrynode(dentrykey(m, str), 0);fs0[ri0[inodekey(ino)]]) ) ) .nsubdirs = 0, adr1 = adr2, adr1 = adr3, adr1 = adr4, adr2 = adr3, adr2 = adr4, adr3 = adr4, adr3 = ri0[inodekey(ino)], adr4 = ri0[inodekey(ino)], m = 0, m = ino, m1 = ROOT_INO, m1 = 0, m1 = ino, mkdentry(str, m2) = mkdentry(str0, m1), (adr3 = ri0[inodekey(ino)] ⊃ inodenode(inodekey(m), md, true, m4, n0, m0) ;(adr2 = ri0[inodekey(ino)] ⊃ dentrynode(dentrykey(m, str0), m2) ;(adr1 = ri0[inodekey(ino)] ⊃ dentrynode(dentrykey(m, str), 0);fs0[ri0[inodekey(ino)]]) ) ) .directory, adr4 ∈ (ri0 -- dentrykey(m, str))[dentrykey(m, str0), adr2][inodekey(m), adr3], adr2 ∈ ri0 -- dentrykey(m, str), adr4 ∈ fs0, adr3 ∈ fs0, adr2 ∈ fs0, adr1 ∈ fs0, inodekey(m) ∈ ro, adr3 ∈ (ri0 -- dentrykey(m, str))[dentrykey(m, str0), adr2]

Rule argument

fma: adr3 = ri0[inodekey(ino)]

Additional information

Used simplifier rules: ⊦ inodenode(key, md, boolvar, m, m0, m1).nsubdirs = m0; (s)% ⊦ key ∈ ri ∧ ri-cons(ri, fs) → ri[key] ∈ fs; (ss) Used formulas: adr3 = ri0[inodekey(ino)]