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Proof step 344 from proof inv-rename-overwrite-reparent (previous step)

m11 + 1 = fs0[ri0[inodekey(m8)]].nlink, ¬ fs0[ri0[inodekey(m8)]].directory ↔ ¬ fs0[ri0[inodekey(m5)]].directory, fs0[ri0[dentrykey(m0, str0)]] = dentrynode(key3, m8), fs0[ri0[inodekey(m0)]] = inodenode(key0, md1, true, m9, m12, m13), fs0[ri0[dentrykey(m, str)]] = dentrynode(key1, m5), fo.inodes?, ro.inodes?, file-node-cons(fs0, ri0), log-cons(log0, fs0), orphans-cons(fs0, ri0, ro), replay-cons-strong(fs0, ri0, ro, fi, fo, log0), ri-cons(ri0, fs0), ri-inj(fi), ri-inj(ri0), ubifs-cons(fs0, ri0, ro, fi, fo, log0), key2 ∈ ri0, ri0[inodekey(m0)] ∈ fs0, dentrykey(m, str) ∈ ri0, inodekey(m5) ∈ ri0, dentrykey(m0, str0) ∈ ri0, inodekey(m8) ∈ ri0, ri0[dentrykey(m, str)] ∈ fs0, inodekey(m) ∈ ri0, inodekey(m0) ∈ ri0, ri0[dentrykey(m0, str0)] ∈ fs0, ri0[inodekey(m)] ∈ fs0, ri0[key2] ∈ fs0, key2.inode? → fs0[ri0[key2]].inode? ∧ key2.ino ≠ 0, key2.dentry? → fs0[ri0[key2]].dentry? ∧ inodekey(key2.ino) ∈ ri0 ∧ inodekey(fs0[ri0[key2]].ino) ∈ ri0 ∧ ¬ inodekey(key2.ino) ∈ ro ∧ ¬ inodekey(fs0[ri0[key2]].ino) ∈ ro ∧ fs0[ri0[inodekey(key2.ino)]].directory, key2.data? → fs0[ri0[key2]].data? ∧ inodekey(key2.ino) ∈ ri0 ∧ ¬ fs0[ri0[inodekey(key2.ino)]].directory ∧ # fs0[ri0[key2]].data = VFS_PAGE_SIZE, fs0[ri0[inodekey(m8)]].directory → dentrykeys(inodekey(m8), ri0) = ∅, m10 ≠ 0 ∨ m = ROOT_INO, m9 ≠ 0 ∨ m0 = ROOT_INO, ¬ fs0[ri0[inodekey(m5)]].directory ∧ ¬ boolvar3 ∨ fs0[ri0[inodekey(m5)]].directory ∧ boolvar3 ∧ m4 = fs0[ri0[inodekey(m5)]].size, ¬ fs0[ri0[inodekey(m5)]].directory ∧ ¬ boolvar1 ∨ fs0[ri0[inodekey(m8)]].directory ∧ boolvar1 ∧ m7 = fs0[ri0[inodekey(m8)]].size ⊦ (adr5 = (dentrykey(m0, str0) = key2 ⊃ adr2;ri0[key2]) ⊃ inodenode(inodekey(m8), md2, boolvar1, m11, fs0[ri0[inodekey(m8)]].nsubdirs, m7) ;(adr4 = (dentrykey(m0, str0) = key2 ⊃ adr2;ri0[key2]) ⊃ inodenode(inodekey(m0), md0, true, m9, m12, m13) ;(adr3 = (dentrykey(m0, str0) = key2 ⊃ adr2;ri0[key2]) ⊃ inodenode(inodekey(m), md, true, m10, n0, m1) ;(adr2 = (dentrykey(m0, str0) = key2 ⊃ adr2;ri0[key2]) ⊃ dentrynode(dentrykey(m0, str0), m5) ;(adr1 = (dentrykey(m0, str0) = key2 ⊃ adr2;ri0[key2]) ⊃ dentrynode(dentrykey(m, str), 0);fs0[(dentrykey(m0, str0) = key2 ⊃ adr2;ri0[key2])]) ) ) ) ) .key = key2, adr1 = adr2, adr1 = adr3, adr1 = adr4, adr1 = adr5, adr2 = adr3, adr2 = adr4, adr2 = adr5, adr3 = adr4, adr3 = adr5, adr4 = adr5, dentrykey(m, str) = dentrykey(m0, str0), inodekey(m8) = key2, inodekey(m0) = key2, inodekey(m) = key2, key2 = dentrykey(m, str), m = 0, m0 = m, m0 = 0, m11 = 0, m8 = ROOT_INO, m8 = 0, adr4 ∈ (ri0 -- dentrykey(m, str))[dentrykey(m0, str0), adr2][inodekey(m), adr3], adr2 ∈ ri0 -- dentrykey(m, str), adr5 ∈ fs0, adr4 ∈ fs0, adr3 ∈ fs0, adr2 ∈ fs0, adr1 ∈ fs0, inodekey(m) ∈ ro, inodekey(m0) ∈ ro, adr3 ∈ (ri0 -- dentrykey(m, str))[dentrykey(m0, str0), adr2], adr5 ∈ (ri0 -- dentrykey(m, str))[dentrykey(m0, str0), adr2][inodekey(m), adr3][inodekey(m0), adr4]

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: dentrykey(m0, str0) = key2

Additional information

Used simplifier rules: ⊦ ri-cons(ri, fs) ∧ key ∈ ri → fs[ri[key]].key = key; (s)% ⊦ inodekey(m) ≠ dentrykey(m0, str); (s)% ⊦ dentrynode(key, m).key = key; (s) Used formulas: dentrykey(m0, str0) = key2