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Proof step 67 from proof inv-rmdir (previous step)

1 = fs0[ri0[inodekey(fs0[ri0[dentrykey(m0, str)]].ino)]].nlink, fs0[ri0[dentrykey(fs0[ri0[dentrykey(m0, str)]].ino, str0)]] = dentrynode(key, m), links(fs0[ri0[dentrykey(m0, str)]].ino, fs0, ri0) = ∅ ++ dentrykey(m0, str), fs0[ri0[dentrykey(m0, str)]].dentry?, fs0[ri0[inodekey(m0)]].directory, fs0[ri0[inodekey(fs0[ri0[dentrykey(m0, str)]].ino)]].directory, fs0[ri0[inodekey(fs0[ri0[dentrykey(m0, str)]].ino)]].inode?, fs0[ri0[inodekey(m0)]].inode?, ro.inodes?, fo.inodes?, file-node-cons(fs0, ri0), log-cons(log0, fs0), orphans-cons(fs0, ri0, ro), replay-cons-strong(fs0, ri0, ro, fi, fo, log0), ri-cons(ri0, fs0), ri-inj(ri0), ri-inj(fi), ubifs-cons(fs0, ri0, ro, fi, fo, log0), inodekey(m) ∈ ri0, dentrykey(fs0[ri0[dentrykey(m0, str)]].ino, str0) ∈ ri0, dentrykey(m0, str) ∈ ri0, inodekey(m0) ∈ ri0, ri0[dentrykey(m0, str)] ∈ fs0, ri0[inodekey(fs0[ri0[dentrykey(m0, str)]].ino)] ∈ fs0, ri0[inodekey(m0)] ∈ fs0, ri0[dentrykey(fs0[ri0[dentrykey(m0, str)]].ino, str0)] ∈ fs0, inodekey(fs0[ri0[dentrykey(m0, str)]].ino) ∈ ri0, 1 ≤ fs0[ri0[inodekey(m0)]].size, 1 ≤ fs0[ri0[inodekey(m0)]].nsubdirs, ∀ key0. ¬ key0 ∈ ri0 ∨ ¬ key0.dentry? ∨ key0.ino ≠ fs0[ri0[dentrykey(m0, str)]].ino, fs0[ri0[inodekey(m0)]].nlink ≠ 0 ∨ m0 = ROOT_INO ⊦ fs0[ri0[dentrykey(m0, str)]].ino = 0, fs0[ri0[dentrykey(m0, str)]].ino = ROOT_INO, fs0[ri0[inodekey(m0)]].nsubdirs = 0, fs0[ri0[inodekey(m0)]].size = 0, adr1 = adr3, adr1 = adr2, adr2 = adr3, dentrykey(fs0[ri0[dentrykey(m0, str)]].ino, str0) = dentrykey(m0, str), m0 = 0, inodekey(m) ∈ ro, inodekey(fs0[ri0[dentrykey(m0, str)]].ino) ∈ ro, inodekey(m0) ∈ ro, adr1 ∈ fs0, adr2 ∈ fs0, adr3 ∈ fs0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 30 terms: dentrykey(fs0[ri0[dentrykey(m0, str)]].ino, str0)

Additional information

Used simplifier rules: ⊦ dentrykey(m, str).dentry?; (s)% ⊦ dentrykey(m, str).ino = m; (s) Used terms: dentrykey(fs0[ri0[dentrykey(m0, str)]].ino, str0)