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Proof step 342 from proof inv-truncate (previous step)

m = 0 ∧ m0 ≠ ROOT_INO ↔ inodekey(m0) ∈ ro, VFS_PAGE_SIZE = n0 + m4 % VFS_PAGE_SIZE, fs0[ri0[dentrykey(ino, str)]] = dentrynode(key, m3), fs0[ri0[datakey(m0, m4 / VFS_PAGE_SIZE)]] = datanode(datakey(m0, m4 / VFS_PAGE_SIZE), buf0), fs0[ri0[inodekey(m0)]] = inodenode(key1, md, false, m, m1, m2), fs0[ri0[inodekey(ino)]].directory, ro.inodes?, fo.inodes?, file-node-cons(fs0, ri0), log-cons(log0, fs0), orphans-cons(fs0, ri0, ro), replay-cons-strong(fs0, ri0, ro, fi, fo, log0), ri-cons(ri0, fs0), ri-inj(ri0), ri-inj(fi), ubifs-cons(fs0, ri0, ro, fi, fo, log0), inodekey(m0) ∈ ri0, ri0[inodekey(m0)] ∈ fs0, datakey(m0, m4 / VFS_PAGE_SIZE) ∈ ri0, ri0[datakey(m0, m4 / VFS_PAGE_SIZE)] ∈ fs0, ri0[dentrykey(ino, str)] ∈ fs0, dentrykey(ino, str) ∈ ri0, inodekey(m3) ∈ ri0, inodekey(ino) ∈ ri0, m4 ≤ n1, ro ⊆ dom ri0 ⊦ m4 % VFS_PAGE_SIZE = 0, adr1 = adr3, adr1 = adr2, adr2 = adr3, adr2 = ri0[inodekey(ino)], adr3 = ri0[inodekey(ino)], m0 = 0, m0 = ino, (adr2 = ri0[inodekey(ino)] ⊃ inodenode(inodekey(m0), md0, false, m, m1, n1) ;(adr1 = ri0[inodekey(ino)] ⊃ truncnode(inodekey(m0), m4);fs0[ri0[inodekey(ino)]]) ) .directory, buf-opt.some?, adr1 ∈ fs0, adr2 ∈ fs0, adr3 ∈ fs0, adr3 ∈ ri0, inodekey(m3) ∈ ro, inodekey(ino) ∈ ro

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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