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Proof step 848 from proof inv-truncate (previous step)

fs[ri[inodekey(m0)]].nlink = 0 ∧ m0 ≠ ROOT_INO ↔ inodekey(m0) ∈ ro, adr = adr2, adr0 = adr1, inode = mkinode(m0, md, false, fs[ri[inodekey(m0)]].nlink, fs[ri[inodekey(m0)]].nsubdirs, m4), nd = nd1, nd0 = truncnode(inodekey(m0), min(n, m4)), nd1 = inodenode(inodekey(m0), md, false, fs[ri[inodekey(m0)]].nlink, fs[ri[inodekey(m0)]].nsubdirs, n), fs[ri[inodekey(m0)]].inode?, fo.inodes?, ro.inodes?, file-node-cons(fs, ri), log-cons(log, fs), orphans-cons(fs, ri, ro), replay-cons-strong(fs, ri, ro, fi, fo, log), ri-inj(fi), ri-inj(ri), ubifs-cons(fs, ri, ro, fi, fo, log), inodekey(m0) ∈ ri, ri[inodekey(m0)] ∈ fs, buf-opt.some? → # buf-opt.buf = VFS_PAGE_SIZE ⊦ fs[ri[inodekey(m0)]].directory, ri-cons(ri, fs) ∧ node-cons(nd0.key, nd0) ∧ node-cons(nd.key, nd), m4 ≤ n ∧ m4 % VFS_PAGE_SIZE ≠ 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ ubifs-cons(fs, ri, ro, fi, fo, log) → ¬ inodekey(0) ∈ ri; (s)% ⊦ ROOT_INO ≠ 0; (s)% ⊦ inodekey(m).ino = m; (s)%⊦ node-cons(key0, inodenode(key1, md, boolvar, n, n0, m)) ↔ key0.inode? ∧ key0.ino ≠ 0; (s)% ⊦ inodenode(key, md, boolvar, m, m0, m1).key = key; (s)% ⊦ inodekey(m).inode?; (s)% ⊦ node-cons(key0, truncnode(key1, n)) ↔ key0.inode?; (s)% ⊦ truncnode(key, m).key = key; (s)% ⊦ ubifs-cons(fs, ri, ro, fi, fo, log) → ri-cons(ri, fs); (ss)