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Proof step 242 from proof inv-unlink (previous step)

m3 + 1 = fs0[ri0[inodekey(fs0[ri0[dentrykey(m1, str)]].ino)]].nlink, fs0[ri0[datakey(ino, n)]].data?, fs0[ri0[dentrykey(m1, str)]].dentry?, (adr2 = ri0[inodekey(ino)] ⊃ dentrynode(dentrykey(m1, str), 0) ;(adr1 = ri0[inodekey(ino)] ⊃ inodenode(inodekey(m1), md0, true, fs0[ri0[inodekey(m1)]].nlink, fs0[ri0[inodekey(m1)]].nsubdirs, fs0[ri0[inodekey(m1)]].size - 1) ;fs0[ri0[inodekey(ino)]] ) ) .directory, fs0[ri0[inodekey(m1)]].directory, fs0[ri0[inodekey(fs0[ri0[dentrykey(m1, str)]].ino)]].inode?, fs0[ri0[inodekey(m1)]].inode?, fo.inodes?, ro.inodes?, file-node-cons(fs0, ri0), log-cons(log0, fs0), orphans-cons(fs0, ri0, ro), replay-cons-strong(fs0, ri0, ro, fi, fo, log0), ri-cons(ri0, fs0), ri-inj(fi), ri-inj(ri0), ubifs-cons(fs0, ri0, ro, fi, fo, log0), inodekey(ino) ∈ ri0, datakey(ino, n) ∈ ri0, dentrykey(m1, str) ∈ ri0, ri0[dentrykey(m1, str)] ∈ fs0, inodekey(fs0[ri0[dentrykey(m1, str)]].ino) ∈ ri0, ri0[inodekey(fs0[ri0[dentrykey(m1, str)]].ino)] ∈ fs0, inodekey(m1) ∈ ri0, ri0[inodekey(m1)] ∈ fs0, ri0[datakey(ino, n)] ∈ fs0, 1 ≤ fs0[ri0[inodekey(m1)]].size, fs0[ri0[inodekey(m1)]].nlink ≠ 0 ∨ m1 = ROOT_INO ⊦ fs0[ri0[dentrykey(m1, str)]].ino = ino, fs0[ri0[dentrykey(m1, str)]].ino = 0, fs0[ri0[dentrykey(m1, str)]].ino = ROOT_INO, fs0[ri0[inodekey(m1)]].size = 0, adr1 = adr3, adr1 = adr2, adr2 = adr3, adr2 = ri0[inodekey(ino)], adr3 = ri0[inodekey(ino)], ino = 0, m1 = 0, m3 = 0, fs0[ri0[inodekey(ino)]].directory, fs0[ri0[inodekey(fs0[ri0[dentrykey(m1, str)]].ino)]].directory, inodekey(m1) ∈ ro, inodekey(fs0[ri0[dentrykey(m1, str)]].ino) ∈ ro, adr1 ∈ fs0, adr2 ∈ fs0, adr3 ∈ fs0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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