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Proof step 58 from proof inv-write-inode (previous step)

fs0[ri[inodekey(m)]].nlink = 0 ∧ m ≠ ROOT_INO ↔ inodekey(m) ∈ ro, fs0[ri[datakey(ino, n)]] = datanode(datakey(ino, n), buf), fs0[(m = ino ⊃ adr1;ri[inodekey(ino)])].directory, fs0[ri[inodekey(m)]].inode?, fo.inodes?, ro.inodes?, file-node-cons(fs0, ri), log-cons(log0, fs0), orphans-cons(fs0, ri, ro), replay-cons-strong(fs0, ri, ro, fi, fo, log0), ri-inj(fi), ri-inj(ri), ubifs-cons(fs0, ri, ro, fi, fo, log0), inodekey(ino) ∈ ri, datakey(ino, n) ∈ ri, ri[datakey(ino, n)] ∈ fs0, ri[inodekey(m)] ∈ fs0, inodekey(m) ∈ ri, ¬ fs0[ri[inodekey(m)]].directory ∧ ¬ boolvar0 ∨ fs0[ri[inodekey(m)]].directory ∧ boolvar0 ∧ m2 = fs0[ri[inodekey(m)]].size ⊦ 0 = m, adr1 = (m = ino ⊃ adr1;ri[inodekey(ino)]), ino = 0, fs0[ri[inodekey(ino)]].directory, adr1 ∈ fs0

Proof step 58 from proof inv-write-inode (previous step)

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

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