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Proof step 35 from proof inv-writepage (previous step)

# buf = VFS_PAGE_SIZE, fs0[ri[dentrykey(ino, str)]] = dentrynode(dentrykey(ino, str), m0), fs0[ri[inodekey(ino)]].directory, ro.inodes?, fo.inodes?, file-node-cons(fs0, ri), log-cons(log0, fs0), orphans-cons(fs0, ri, ro), replay-cons-strong(fs0, ri, ro, fi, fo, log0), ri-inj(ri), ri-inj(fi), ubifs-cons(fs0, ri, ro, fi, fo, log0), inodekey(ino) ∈ ri, inodekey(m0) ∈ ri, ri[dentrykey(ino, str)] ∈ fs0, dentrykey(ino, str) ∈ ri, inodekey(m) ∈ ri ⊦ (adr1 = ri[inodekey(ino)] ⊃ datanode(datakey(m, pageno), buf);fs0[ri[inodekey(ino)]]).directory, fs0[ri[inodekey(m)]].directory, inodekey(ino) ∈ ro, inodekey(m0) ∈ ro, adr1 ∈ fs0

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: adr1 = ri[inodekey(ino)]

Additional information

Used simplifier rules: ⊦ dentrykey(ino, str) ∈ ri ∧ ubifs-cons(fs, ri, ro, fi, fo, log) → fs[ri[inodekey(ino)]].directory; (ss)% ⊦ ¬ adr ∈ fs → fs[adr] = (∅)[adr]; (s)% ⊦ key ∈ ri ∧ ubifs-cons(fs, ri, ro, fi, fo, log) → ri[key] ∈ fs; (ss) Used formulas: adr1 = ri[inodekey(ino)]