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Proof step 15 from proof replay-prog (previous step)

boolvar ↔ true, ax = log, err = ESUCCESS, err = err0, fi0 = fi, fo0 = fo, fs0 = fs, ks = ro, log0 = log, ri = fi, ro = fo, fo.inodes?, replay-safe(log, fs, fi ⊖ fo), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪aubifs_replayorphans#(fi, fo, fs, log, boolvar; ks, err, ri, ro); if err = ESUCCESS then aubifs_replaylog#(ax, fi, ro, fo, fs, log, boolvar; err, ri); if err = ESUCCESS then aubifs_core_journal_sync#(ri, fi, ro, fo, fs, log; ; boolvar, err)⟫ ( (err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → ri = replay-log(log0, fs0, fi0 ⊖ fo0) ∧ ro = ∅ ∧ fs = fs0 ∧ fi = fi0 ∧ fo = fo0 ∧ log = log0 ∧ boolvar))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
err0 = ESUCCESS, ks = fo, ri = fi, ro = fo, fo.inodes?, replay-safe(log, fs, fi ⊖ fo) ⊦ ⟪aubifs_replayorphans#(fi, fo, fs, log, true; ks, err0, ri, ro); boolvar := true; if err0 = ESUCCESS then aubifs_replaylog#(log, fi, ro, fo, fs, log, boolvar; err0, ri); if err0 = ESUCCESS then aubifs_core_journal_sync#(ri, fi, ro, fo, fs, log; ; boolvar, err0)⟫ ((err0 = ESUCCESS ∨ ⌊err0⌋ ) ∧ (err0 = ESUCCESS → ri = replay-log(log, fs, fi ⊖ fo) ∧ ro = ∅ ∧ boolvar))

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ ⌊ESUCCESS⌋ ; (s)