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Proof step 103 from proof replayone-prog (previous step)

boolvar ↔ boolvar0, fs[adr].data?, node-cons(fs[adr].key, fs[adr]), adr ∈ fs, ¬ fs[adr].dentry?, ¬ fs[adr].inode?, ¬ adr ∈ ri ⊦ ⟪aubifs_core_index_contains#(inodekey(fs[adr].key.ino), ri, fi, ro, fo, fs, log, boolvar0; boolvar; err); ri0 := ri; nd := fs[adr]; if err = ESUCCESS ∧ boolvar then aubifs_core_index_store#(nd.key, adr, fi, ro, fo, fs, log, boolvar0; ri); if nd.trunc? then aubifs_core_index_truncate#(nd.key, nd.size, fi, ro, fo, fs, log, boolvar0; ri)⟫ ((err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → ri = replay-one(adr, fs[adr], ri0)))

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: node name: elim-05 seq: ⊦ nd.data? → (key = nd.key ∧ buf = nd.data ↔ nd = datanode(key, buf)) subst: [nd, key, buf] → [fs[adr], key, buf]

Additional information

Used simplifier rules: ⊦ nd.data? → (key = nd.key ∧ buf = nd.data ↔ nd = datanode(key, buf)); (elim) Used terms: fs[adr], key, buf