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Proof step 26 from proof replayone-prog (previous step)

boolvar ↔ boolvar0, boolvar2 ↔ boolvar0, fs[adr] = inodenode(inodekey(ino), md, boolvar1, m, m0, m1), err = ESUCCESS, key = inodekey(ino), nd = fs[adr], ri = ri1[key, adr], ri0 = ri1, adr ∈ fs, m ≠ 0 ∨ ino = ROOT_INO ⊦ ⟪skip⟫ ((err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → ri = replay-one(adr, fs[adr], ri0))), ino = 0, adr ∈ ri1

Heuristic symbolic execution applied rule skip right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ replay-one(adr, inodenode(key, md, boolvar, n, n0, m), ri) = (n ≠ 0 ∨ key.ino = ROOT_INO ⊃ ri[key, adr] ;(boolvar ⊃ ri -- key;ri ⊖ key) ); (s)% ⊦ inodekey(m).ino = m; (s)