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Proof step 28 from proof replayone-prog (previous step)

nd.nlink = 0, boolvar ↔ boolvar0, err = ESUCCESS, nd = fs[adr], ri0 = ri, nd.inode?, node-cons(fs[adr].key, fs[adr]), adr ∈ fs ⊦ ⟪aubifs_core_index_truncate#(nd.key, 0, fi, ro, fo, fs, log, boolvar0; ri); if err = ESUCCESS then aubifs_core_index_remove#(nd.key, fi, ro, fo, fs, log, boolvar0; ri); if nd.dentry? then if nd.ino ≠ 0 then aubifs_core_index_store#(nd.key, adr, fi, ro, fo, fs, log, boolvar0; ri) else aubifs_core_index_remove#(nd.key, fi, ro, fo, fs, log, boolvar0; ri); if nd.data? then {let key = inodekey(nd.key.ino) in aubifs_core_index_contains#(key, ri, fi, ro, fo, fs, log, boolvar0; boolvar; err); if err = ESUCCESS ∧ boolvar then aubifs_core_index_store#(nd.key, adr, fi, ro, fo, fs, log, boolvar0; ri)}; if nd.trunc? then aubifs_core_index_truncate#(nd.key, nd.size, fi, ro, fo, fs, log, boolvar0; ri)⟫ ((err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → ri = replay-one(adr, fs[adr], ri0))), nd.key.ino = ROOT_INO, nd.directory, adr ∈ ri

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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