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Proof step 67 from proof replayone-prog (previous step)

boolvar ↔ boolvar0, boolvar1 ↔ boolvar0, fs[adr] = inodenode(inodekey(ino), md, true, 0, m0, m1), err = ESUCCESS, key = inodekey(ino), nd = fs[adr], ri = ri1 -- key, ri0 = ri1, adr ∈ fs ⊦ ⟪skip⟫ ((err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → ri = replay-one(adr, fs[adr], ri0))), ino = ROOT_INO, ino = 0, adr ∈ ri1

Heuristic symbolic execution applied rule skip right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ replay-one(adr, inodenode(key, md, boolvar, n, n0, m), ri) = (n ≠ 0 ∨ key.ino = ROOT_INO ⊃ ri[key, adr] ;(boolvar ⊃ ri -- key;ri ⊖ key) ); (s)% ⊦ inodekey(m).ino = m; (s)