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Proof step 84 from proof replayone-prog (previous step)

boolvar1 ↔ boolvar0, boolvar ↔ boolvar0, fs[adr] = dentrynode(dentrykey(ino, str), m), err = ESUCCESS, key = dentrykey(ino, str), nd = fs[adr], ri = ri1[key, adr], ri0 = ri1, adr ∈ fs ⊦ ⟪if nd.trunc? then aubifs_core_index_truncate#(nd.key, nd.size, fi, ro, fo, fs, log, boolvar0; ri)⟫ ((err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → ri = replay-one(adr, fs[adr], ri0))), m = 0, adr ∈ ri1

Heuristic symbolic execution applied rule if negative right

And obtained the following new goals

Proof step 85:
boolvar ↔ boolvar0, boolvar1 ↔ boolvar0, fs[adr] = dentrynode(dentrykey(ino, str), m), err = ESUCCESS, key = dentrykey(ino, str), nd = fs[adr], ri = ri1[key, adr], ri0 = ri1, adr ∈ fs ⊦ ⟪skip⟫ ((err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → ri = replay-one(adr, fs[adr], ri0))), m = 0, adr ∈ ri1

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ ¬ dentrynode(key, m).trunc?; (s)