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Proof step 22 from proof eq-io-readdir (previous step)

⟨fail#(; ; err)⟩ (err = err0), dirs1[m] = mkdir(m3, md0, m4, m5, entries), m ∈ dirs1 ⊦ ∃ strings. ⟨strings0 := strings; fail#(; ; err)⟩ (strings0 = strings1 ∧ err = err0), dom entries = strings1 ∧ ESUCCESS = err0

Heuristic unfold applied rule call left

And obtained the following new goals

Proof step 23:
⟨choose err0 with ⌊err0⌋ in err := err0⟩ (err = err0), dirs1[m] = mkdir(m3, md0, m4, m5, entries), m ∈ dirs1 ⊦ ∃ strings. ⟨strings0 := strings; fail#(; ; err)⟩ (strings0 = strings1 ∧ err = err0), dom entries = strings1 ∧ ESUCCESS = err0

Rule argument

pos: left 1

Additional information

Used simplifier rules: fail#(; ; ERR){choose ERR0 with ⌊ERR0⌋ in ERR := ERR0};