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Proof step 28 from proof eq-io-readdir (previous step)

dirs1[m] = mkdir(m3, md0, m4, m5, entries), m ∈ dirs1, ⌊err1⌋ ⊦ ⟨fail#(; ; err)⟩ (strings1 = strings1 ∧ err = err1), ∃ strings. ⟨strings0 := strings; fail#(; ; err)⟩ (strings0 = strings1 ∧ err = err1)

Heuristic unfold applied rule call right

And obtained the following new goals

Proof step 29:
dirs1[m] = mkdir(m3, md0, m4, m5, entries), m ∈ dirs1, ⌊err1⌋ ⊦ ⟨choose err0 with ⌊err0⌋ in err := err0⟩ (strings1 = strings1 ∧ err = err1), ∃ strings. ⟨strings0 := strings; fail#(; ; err)⟩ (strings0 = strings1 ∧ err = err1)

Rule argument

pos: right 1

Additional information

Used simplifier rules: fail#(; ; ERR){choose ERR0 with ⌊ERR0⌋ in ERR := ERR0};