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Proof step 128 from proof initialization (previous step)

⌊err0⌋ ⊦ ⟨fail#(; ; err)⟩ (dirs1 = dirs1 ∧ files1 = files1 ∧ (boolvar ↔ boolvar) ∧ err0 = err)

Heuristic unfold applied rule call right

And obtained the following new goals

Proof step 129:
⌊err0⌋ ⊦ ⟨choose err0 with ⌊err0⌋ in err := err0⟩ (dirs1 = dirs1 ∧ files1 = files1 ∧ (boolvar ↔ boolvar) ∧ err0 = err)

Rule argument

pos: right 1

Additional information

Used simplifier rules: fail#(; ; ERR){choose ERR0 with ⌊ERR0⌋ in ERR := ERR0};