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Proof step 149 from proof initialization (previous step)

⌊err0⌋ ⊦ ∃ dirs, files, asynced. ⟨fail#(; ; err)⟩ (dirs1 = dirs ∧ files1 = files ∧ (boolvar ↔ asynced) ∧ err0 = err)

User applied rule exists right

And obtained the following new goals

Proof step 150:
⌊err0⌋ ⊦ ⟨fail#(; ; err)⟩ (dirs1 = dirs1 ∧ files1 = files1 ∧ (boolvar ↔ boolvar) ∧ err0 = err)

Rule argument

pos: right 1 terms: dirs1, files1, boolvar abort: F discard: T computed: F

Additional information

Used terms: dirs1, files1, boolvar