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Proof step 523 from proof refine-rename-new-reparent (previous step)

n0 + (boolvar1 ⊃ 1;0) = fs[ri[inodekey(m3)]].nsubdirs, m11 + 1 = fs[ri[inodekey(m3)]].size, fs[ri[inodekey(m3)]].directory, fs[ri[inodekey(m7)]].directory, orphans(fs, ri).inodes?, fo.inodes?, afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), file-node-cons(fs, ri), log-cons(log, fs), orphans-cons(fs, ri, orphans(fs, ri)), replay-cons-strong(fs, ri, orphans(fs, ri), fi, fo, log), ri-inj(ri), ri-inj(fi), ubifs-cons(fs, ri, orphans(fs, ri), fi, fo, log), inodekey(m3) ∈ ri, inodekey(fs[ri[dentrykey(m3, str)]].ino) ∈ ri, dentrykey(m3, str) ∈ ri, inodekey(m7) ∈ ri, boolvar3 → boolvar0, ∀ adr, adr0, adr1, adr2. adr ∈ fs ∨ adr0 ∈ fs ∨ adr1 ∈ fs ∨ adr2 ∈ fs ∨ adr = adr0 ∨ adr = adr1 ∨ adr = adr2 ∨ adr0 = adr1 ∨ adr0 = adr2 ∨ adr1 = adr2, fs[ri[inodekey(m3)]].nlink ≠ 0 ∨ m3 = ROOT_INO, fs[ri[inodekey(m7)]].nlink ≠ 0 ∨ m7 = ROOT_INO, links(m3, abs-dirs(fs, ri)) ≠ ∅ ∨ m3 = ROOT_INO, links(m7, abs-dirs(fs, ri)) ≠ ∅ ∨ m7 = ROOT_INO, ¬ fs[ri[inodekey(fs[ri[dentrykey(m3, str)]].ino)]].directory ∧ ¬ boolvar1 ∧ m0 = fs[ri[inodekey(fs[ri[dentrykey(m3, str)]].ino)]].nlink ∧ m1 = fs[ri[inodekey(fs[ri[dentrykey(m3, str)]].ino)]].nsubdirs ∨ fs[ri[inodekey(fs[ri[dentrykey(m3, str)]].ino)]].directory ∧ boolvar1 ∧ m0 = fs[ri[inodekey(fs[ri[dentrykey(m3, str)]].ino)]].nlink ∧ m1 = fs[ri[inodekey(fs[ri[dentrykey(m3, str)]].ino)]].nsubdirs ∧ m2 = fs[ri[inodekey(fs[ri[dentrykey(m3, str)]].ino)]].size, fs[ri[inodekey(fs[ri[dentrykey(m3, str)]].ino)]].directory ∧ m0 = fs[ri[inodekey(fs[ri[dentrykey(m3, str)]].ino)]].nlink ∧ m2 = fs[ri[inodekey(fs[ri[dentrykey(m3, str)]].ino)]].size ∧ m1 = fs[ri[inodekey(fs[ri[dentrykey(m3, str)]].ino)]].nsubdirs ∧ boolvar1 ∨ ¬ fs[ri[inodekey(fs[ri[dentrykey(m3, str)]].ino)]].directory ∧ m0 = fs[ri[inodekey(fs[ri[dentrykey(m3, str)]].ino)]].nlink ∧ m1 = 0 ∧ ¬ boolvar1 ⊦ ⟨asynced := ?⟩ ((asynced → boolvar2) ∧ ENOSPC = ENOSPC), m3 = m7, dentrykey(m7, str0) ∈ ri, ( (fs[ri[inodekey(m7)]].inode? ∧ ri[inodekey(m7)] ∈ fs ∧ inodekey(m7) ∈ ri) ∧ (fs[ri[inodekey(m7)]].inode? ∧ ri[inodekey(m7)] ∈ fs ∧ inodekey(m7) ∈ ri) ∧ (fs[ri[inodekey(m7)]].trunc? ∨ fs[ri[inodekey(m7)]].inode?) ∧ ri[inodekey(m7)] ∈ fs ∧ inodekey(m7) ∈ ri) ∧ fs[ri[inodekey(m3)]].inode? ∧ ri[inodekey(m3)] ∈ fs ∧ inodekey(m3) ∈ ri, fs[ri[inodekey(m7)]].nlink = 0 ∧ m7 ≠ ROOT_INO, fs[ri[inodekey(m3)]].nlink = 0 ∧ m3 ≠ ROOT_INO

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ inodekey(ino) ∈ ri ∧ ri[inodekey(ino)] ∈ fs ∧ ubifs-cons(fs, ri, ro, fi, fo, log) → fs[ri[inodekey(ino)]].inode?; (ss)% ⊦ key ∈ ri ∧ ubifs-cons(fs, ri, ro, fi, fo, log) → ri[key] ∈ fs; (ss)