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Proof step 437 from proof refine-rmdir (previous step)

1 = fs[ri[inodekey(fs[ri[dentrykey(m, str)]].ino)]].nlink, abs-children(fs[ri[dentrykey(m, str)]].ino, fs, ri) = ∅, dentrykeys(inodekey(fs[ri[dentrykey(m, str)]].ino), ri) = ∅, links(fs[ri[dentrykey(m, str)]].ino, fs, ri) = ∅ ++ dentrykey(m, str), fs[ri[inodekey(fs[ri[dentrykey(m, str)]].ino)]].directory, fs[ri[inodekey(m)]].directory, orphans(fs, ri).inodes?, fo.inodes?, afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), file-node-cons(fs, ri), log-cons(log, fs), orphans-cons(fs, ri, orphans(fs, ri)), replay-cons-strong(fs, ri, orphans(fs, ri), fi, fo, log), ri-cons(ri, fs), ri-inj(ri), ri-inj(fi), ubifs-cons(fs, ri, orphans(fs, ri), fi, fo, log), inodekey(m) ∈ ri, inodekey(fs[ri[dentrykey(m, str)]].ino) ∈ ri, dentrykey(m, str) ∈ ri, 1 ≤ fs[ri[inodekey(m)]].nsubdirs, 1 ≤ fs[ri[inodekey(m)]].size, asynced → boolvar0, ∀ adr, adr0, adr1. adr ∈ fs ∨ adr0 ∈ fs ∨ adr1 ∈ fs ∨ adr = adr0 ∨ adr = adr1 ∨ adr0 = adr1, links(m, abs-dirs(fs, ri)) ≠ ∅ ∨ m = ROOT_INO, fs[ri[inodekey(m)]].nlink ≠ 0 ∨ m = ROOT_INO ⊦ ⟨fail#(; ; err); asynced := ?⟩ ((asynced → boolvar) ∧ ENOSPC = err), fs[ri[dentrykey(m, str)]].ino = 0, fs[ri[dentrykey(m, str)]].ino = ROOT_INO, fs[ri[inodekey(m)]].nsubdirs = 0, fs[ri[inodekey(m)]].size = 0, m = 0, fs[ri[inodekey(m)]].nlink = 0 ∧ m ≠ ROOT_INO, (fs[ri[inodekey(m)]].inode? ∧ ri[inodekey(m)] ∈ fs ∧ inodekey(m) ∈ ri) ∧ (fs[ri[inodekey(m)]].inode? ∧ ri[inodekey(m)] ∈ fs ∧ inodekey(m) ∈ ri) ∧ (fs[ri[inodekey(m)]].trunc? ∨ fs[ri[inodekey(m)]].inode?) ∧ ri[inodekey(m)] ∈ fs ∧ inodekey(m) ∈ ri

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ key ∈ ri ∧ ri-cons(ri, fs) → ri[key] ∈ fs; (ss)%⊦ inodekey(ino) ∈ ri ∧ ri[inodekey(ino)] ∈ fs ∧ ubifs-cons(fs, ri, ro, fi, fo, log) → fs[ri[inodekey(ino)]].inode?; (ss)