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Proof step 1488 from proof refine-truncate (previous step)

0 = fs[ri[inodekey(m)]].nsubdirs, fo.inodes?, orphans(fs, ri).inodes?, afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), file-node-cons(fs, ri), log-cons(log, fs), orphans-cons(fs, ri, orphans(fs, ri)), replay-cons-strong(fs, ri, orphans(fs, ri), fi, fo, log), ri-inj(fi), ri-inj(ri), ubifs-cons(fs, ri, orphans(fs, ri), fi, fo, log), inodekey(m) ∈ ri, buf-opt0.some? → # buf-opt0.buf = VFS_PAGE_SIZE, asynced → boolvar0, ∀ adr, adr0. adr ∈ fs ∨ adr0 ∈ fs ∨ adr = adr0 ⊦ ⟨fail#(; ; err); asynced := ?⟩ ((asynced → boolvar4) ∧ ENOSPC = err), fs[ri[inodekey(m)]].directory, m2 ≤ n ∧ m2 % VFS_PAGE_SIZE ≠ 0, (fs[ri[inodekey(m)]].inode? ∧ ri[inodekey(m)] ∈ fs ∧ inodekey(m) ∈ ri) ∧ fs[ri[inodekey(m)]].inode? ∧ ri[inodekey(m)] ∈ fs ∧ inodekey(m) ∈ ri

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ key ∈ ri ∧ ubifs-cons(fs, ri, ro, fi, fo, log) → ri[key] ∈ fs; (ss)%⊦ inodekey(ino) ∈ ri ∧ ri[inodekey(ino)] ∈ fs ∧ ubifs-cons(fs, ri, ro, fi, fo, log) → fs[ri[inodekey(ino)]].inode?; (ss)