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Proof step 574 from proof refine-unlink (previous step)

m5 + 1 = fs[ri[inodekey(m0)]].nlink, 0 = fs[ri[inodekey(m0)]].nsubdirs, fs[ri[dentrykey(m, str)]] = dentrynode(key, m0), fs[ri[inodekey(m)]] = inodenode(key0, md1, boolvar1, m1, m2, m3), boolvar1, dirs = abs-dirs(fs, ri), files = abs-files(fs, ri), old_dent = mkdentry(str, m0), p_inode0 = mkinode(m, md, true, m1, m2, m3), p_inode1 = mkinode(m0, md0, false, m5 + 1, 0, m6), fs[ri[inodekey(m)]].inode?, fo.inodes?, orphans(fs, ri).inodes?, afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), file-node-cons(fs, ri), log-cons(log, fs), orphans-cons(fs, ri, orphans(fs, ri)), replay-cons-strong(fs, ri, orphans(fs, ri), fi, fo, log), ri-cons(ri, fs), ri-inj(fi), ri-inj(ri), ubifs-cons(fs, ri, orphans(fs, ri), fi, fo, log), inodekey(m) ∈ ri, ri[inodekey(m)] ∈ fs, inodekey(m0) ∈ ri, ri[dentrykey(m, str)] ∈ fs, dentrykey(m, str) ∈ ri, 1 ≤ m3, ⌊err0⌋ , m5 = 0 → links(m0, fs, ri) = ∅ ++ dentrykey(m, str), asynced → boolvar0, links(m, abs-dirs(fs, ri)) ≠ ∅ ∨ m = ROOT_INO, m1 ≠ 0 ∨ m = ROOT_INO ⊦ ⟨afs_unlink#(; p_inode0, p_inode1, old_dent, err1, dirs, files; asynced)⟩ ( dirs = abs-dirs(fs, ri) ∧ files = abs-files(fs, ri) ∧ (asynced → boolvar) ∧ mkinode(m, md, true, m1, m2, m3) = p_inode0 ∧ mkinode(m0, md0, false, m5 + 1, 0, m6) = p_inode1 ∧ mkdentry(str, m0) = old_dent ∧ err0 = err1), m = 0, m0 = ROOT_INO, m0 = 0, m3 = 0, fs[ri[inodekey(m0)]].directory

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ inodenode(key, md, boolvar, m, m0, m1).inode?; (s)%not-zero: 0 < n ⊦ (* n) ≤ m → m ≠ 0; (forward) from specification nat