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Proof step 235 from proof refine-write-inode (previous step)

fo.inodes?, orphans(fs, ri).inodes?, afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), file-node-cons(fs, ri), log-cons(log, fs), orphans-cons(fs, ri, orphans(fs, ri)), replay-cons-strong(fs, ri, orphans(fs, ri), fi, fo, log), ri-inj(fi), ri-inj(ri), ubifs-cons(fs, ri, orphans(fs, ri), fi, fo, log), asynced → boolvar, inodekey(m) ∈ ri ∧ fs[ri[inodekey(m)]].directory ∧ m0 = fs[ri[inodekey(m)]].nlink ∧ m2 = fs[ri[inodekey(m)]].size ∧ m1 = fs[ri[inodekey(m)]].nsubdirs ∧ boolvar0 ∨ inodekey(m) ∈ ri ∧ ¬ fs[ri[inodekey(m)]].directory ∧ m0 = fs[ri[inodekey(m)]].nlink ∧ m1 = 0 ∧ ¬ boolvar0 ⊦ ( inodekey(m) ∈ ri ∧ ¬ fs[ri[inodekey(m)]].directory ∧ ¬ boolvar0 ∧ m0 = fs[ri[inodekey(m)]].nlink ∧ m1 = fs[ri[inodekey(m)]].nsubdirs ∨ inodekey(m) ∈ ri ∧ fs[ri[inodekey(m)]].directory ∧ boolvar0 ∧ m0 = fs[ri[inodekey(m)]].nlink ∧ m1 = fs[ri[inodekey(m)]].nsubdirs ∧ m2 = fs[ri[inodekey(m)]].size) ∧ (fs[(∅)[inodekey(m)]].nlink = 0 ∧ m ≠ ROOT_INO → inodekey(m) ∈ ri)

Heuristic nonsplitting cut applied rule cut formula

And obtained the following new goals

Rule argument

fma: inodekey(m) ∈ ri

Additional information

Used formulas: inodekey(m) ∈ ri