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Proof step 59 from proof refine-write-inode (previous step)

fs0[ri[inodekey(m)]] = inodenode(key, md0, true, m0, m1, m3), (adr1 = ri[dentrykey(m, str)] ⊃ inodenode(inodekey(m), md, true, m0, m1, m3);fs0[ri[dentrykey(m, str)]]).ino ≠ fs0[ri[dentrykey(m, str)]].ino, m ≠ 0, orphans(fs0, ri).inodes?, fo.inodes?, afs-cons(abs-dirs(fs0, ri), abs-files(fs0, ri)), afs-cons(abs-dirs(fs0, ri)[m, abs-dirs(fs0, ri)[m].meta:= md], abs-files(fs0, ri)), file-node-cons(fs0, ri), log-cons(log0, fs0), orphans-cons(fs0, ri, orphans(fs0, ri)), replay-cons-strong(fs0, ri, orphans(fs0, ri), fi, fo, log0), ri-cons(ri, fs0), ri-inj(ri), ri-inj(fi), ubifs-cons(fs0, ri, orphans(fs0, ri), fi, fo, log0), inodekey(m) ∈ ri, ri[inodekey(m)] ∈ fs0, dentrykey(m, str) ∈ ri, ¬ adr1 ∈ fs0, asynced0 → boolvar1 ⊦ ∃ err0. ⌊err0⌋ ∧ ⟨err := err0; asynced0 := ?⟩ ( abs-dirs(fs0, ri) = abs-dirs(fs0[adr1, inodenode(inodekey(m), md, true, m0, m1, m3)], ri[inodekey(m), adr1]) ∧ abs-files(fs0, ri) = abs-files(fs0[adr1, inodenode(inodekey(m), md, true, m0, m1, m3)], ri[inodekey(m), adr1]) ∧ orphans(fs0[adr1, inodenode(inodekey(m), md, true, m0, m1, m3)], ri[inodekey(m), adr1]) = orphans(fs0, ri) ∧ (asynced0 → boolvar) ∧ ESUCCESS = err)

Heuristic nonsplitting cut applied rule cut formula

And closed the goal!

Rule argument

fma: adr1 = ri[dentrykey(m, str)]

Additional information

Used simplifier rules: ⊦ ¬ adr ∈ fs → fs[adr] = (∅)[adr]; (s)% ⊦ key ∈ ri ∧ ri-cons(ri, fs) → ri[key] ∈ fs; (ss) Used formulas: adr1 = ri[dentrykey(m, str)]