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Proof step 125 from proof rename-precond-abs (previous step)

⊦ afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)) ∧ ino ∈ abs-dirs(fs, ri) ∧ subdirs(ino, abs-dirs(fs, ri)) ≠ ∅ → fs[ri[inodekey(ino)]].nsubdirs ≥ 1

Lemma afs-cons-abs-dir-subdirs