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Proof step 54 from proof rename-precond-abs (previous step)

fs[ri[inodekey(m4)]].directory, fs[ri[inodekey(m3)]].directory, fs[ri[inodekey(fs[ri[dentrykey(m3, str0)]].ino)]].directory, fs[ri[inodekey(fs[ri[dentrykey(m4, str)]].ino)]].directory, orphans(fs, ri).inodes?, afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), file-node-cons(fs, ri), log-cons(log, fs), replay-cons-strong(fs, ri, orphans(fs, ri), fi, fo, log), ri-inj(fi), ri-inj(ri), ubifs-cons(fs, ri, orphans(fs, ri), fi, fo, log), inodekey(fs[ri[dentrykey(m3, str0)]].ino) ∈ ri, inodekey(fs[ri[dentrykey(m4, str)]].ino) ∈ ri, dentrykey(m4, str) ∈ ri, inodekey(m3) ∈ ri, inodekey(m4) ∈ ri, dentrykey(m3, str0) ∈ ri, m3 = m4 → md = md0, ∀ str. (str ∈ abs-children(fs[ri[dentrykey(m3, str0)]].ino, fs, ri) ↔ str ∈ ∅) ∧ abs-children(fs[ri[dentrykey(m3, str0)]].ino, fs, ri)[str] = (∅)[str], links(m4, abs-dirs(fs, ri)) ≠ ∅ ∨ m4 = ROOT_INO, links(m3, abs-dirs(fs, ri)) ≠ ∅ ∨ m3 = ROOT_INO ⊦ # dentrykeys(inodekey(fs[ri[dentrykey(m3, str0)]].ino), ri) = 0, fs[ri[dentrykey(m3, str0)]].ino = ROOT_INO, dentrykeys(inodekey(fs[ri[dentrykey(m3, str0)]].ino), ri) = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 55:
fs[ri[inodekey(fs[ri[dentrykey(m4, str)]].ino)]].directory, fs[ri[inodekey(fs[ri[dentrykey(m3, str0)]].ino)]].directory, fs[ri[inodekey(m3)]].directory, fs[ri[inodekey(m4)]].directory, orphans(fs, ri).inodes?, afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), file-node-cons(fs, ri), log-cons(log, fs), replay-cons-strong(fs, ri, orphans(fs, ri), fi, fo, log), ri-inj(ri), ri-inj(fi), ubifs-cons(fs, ri, orphans(fs, ri), fi, fo, log), dentrykey(m3, str0) ∈ ri, inodekey(m4) ∈ ri, inodekey(m3) ∈ ri, dentrykey(m4, str) ∈ ri, inodekey(fs[ri[dentrykey(m4, str)]].ino) ∈ ri, inodekey(fs[ri[dentrykey(m3, str0)]].ino) ∈ ri, m3 = m4 → md = md0, ∀ str1. ¬ dentrykey(fs[ri[dentrykey(m3, str0)]].ino, str1) ∈ ri ∧ abs-children(fs[ri[dentrykey(m3, str0)]].ino, fs, ri)[str1] = (∅)[str1], links(m3, abs-dirs(fs, ri)) ≠ ∅ ∨ m3 = ROOT_INO, links(m4, abs-dirs(fs, ri)) ≠ ∅ ∨ m4 = ROOT_INO ⊦ # dentrykeys(inodekey(fs[ri[dentrykey(m3, str0)]].ino), ri) = 0, fs[ri[dentrykey(m3, str0)]].ino = ROOT_INO, dentrykeys(inodekey(fs[ri[dentrykey(m3, str0)]].ino), ri) = ∅

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ str ∈ ∅; (s)% ⊦ str ∈ abs-children(ino, fs, ri) ↔ dentrykey(ino, str) ∈ ri; (s)