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Proof step 59 from proof rename-precond-abs (previous step)

key = dentrykey(m, str2), m = fs[ri[dentrykey(m3, str0)]].ino, key.dentry?, fs[ri[inodekey(fs[ri[dentrykey(m4, str)]].ino)]].directory, fs[ri[inodekey(m)]].directory, fs[ri[inodekey(m3)]].directory, fs[ri[inodekey(m4)]].directory, orphans(fs, ri).inodes?, afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), file-node-cons(fs, ri), log-cons(log, fs), replay-cons-strong(fs, ri, orphans(fs, ri), fi, fo, log), ri-inj(ri), ri-inj(fi), ubifs-cons(fs, ri, orphans(fs, ri), fi, fo, log), dentrykey(m3, str0) ∈ ri, inodekey(m4) ∈ ri, inodekey(m3) ∈ ri, dentrykey(m4, str) ∈ ri, inodekey(fs[ri[dentrykey(m4, str)]].ino) ∈ ri, inodekey(m) ∈ ri, key ∈ ri, m3 = m4 → md = md0, ∀ str1. ¬ dentrykey(m, str1) ∈ ri ∧ abs-children(m, fs, ri)[str1] = (∅)[str1], links(m3, abs-dirs(fs, ri)) ≠ ∅ ∨ m3 = ROOT_INO, links(m4, abs-dirs(fs, ri)) ≠ ∅ ∨ m4 = ROOT_INO ⊦ # dentrykeys(inodekey(m), ri) = 0, dentrykeys(inodekey(m), ri) = ∅, m = ROOT_INO

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 60:
fs[ri[inodekey(m4)]].directory, fs[ri[inodekey(m3)]].directory, fs[ri[inodekey(fs[ri[dentrykey(m3, str0)]].ino)]].directory, fs[ri[inodekey(fs[ri[dentrykey(m4, str)]].ino)]].directory, orphans(fs, ri).inodes?, afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), file-node-cons(fs, ri), log-cons(log, fs), replay-cons-strong(fs, ri, orphans(fs, ri), fi, fo, log), ri-inj(fi), ri-inj(ri), ubifs-cons(fs, ri, orphans(fs, ri), fi, fo, log), dentrykey(fs[ri[dentrykey(m3, str0)]].ino, str2) ∈ ri, inodekey(fs[ri[dentrykey(m4, str)]].ino) ∈ ri, dentrykey(m4, str) ∈ ri, inodekey(m3) ∈ ri, inodekey(m4) ∈ ri, dentrykey(m3, str0) ∈ ri, inodekey(fs[ri[dentrykey(m3, str0)]].ino) ∈ ri, m3 = m4 → md = md0, ∀ str1. ¬ dentrykey(fs[ri[dentrykey(m3, str0)]].ino, str1) ∈ ri ∧ abs-children(fs[ri[dentrykey(m3, str0)]].ino, fs, ri)[str1] = (∅)[str1], links(m4, abs-dirs(fs, ri)) ≠ ∅ ∨ m4 = ROOT_INO, links(m3, abs-dirs(fs, ri)) ≠ ∅ ∨ m3 = ROOT_INO ⊦ # dentrykeys(inodekey(fs[ri[dentrykey(m3, str0)]].ino), ri) = 0, fs[ri[dentrykey(m3, str0)]].ino = ROOT_INO, dentrykeys(inodekey(fs[ri[dentrykey(m3, str0)]].ino), ri) = ∅

Rule argument

Additional information

Used simplifier rules: ubifs-parent-in: ⊦ dentrykey(ino, str) ∈ ri ∧ ubifs-cons(fs, ri, ro, fi, fo, log) → inodekey(ino) ∈ ri; (forward) from specification aubifs-inv% ⊦ dentrykey(m, str).dentry?; (s)