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Proof step 16 from proof valid-parent-ino-precond (previous step)

⊦ afs-cons(dirs, files) → (links(ino, dirs) = ∅ ↔ (ino ∈ dirs → dirs[ino].nlink = 0) ∧ (ino ∈ files → files[ino].nlink = 0))

A spec-lemma