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Proof step 18 from proof valid-parent-ino-precond (previous step)

fs[ri[inodekey(m)]].directory, ro.inodes?, fo.inodes?, afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), log-cons(log, fs), replay-cons-strong(fs, ri, ro, fi, fo, log), ri-inj(ri), ri-inj(fi), ubifs-cons(fs, ri, ro, fi, fo, log), inodekey(m) ∈ ri, inodekey(m) ∈ ro, ∀ ino. inodekey(ino) ∈ ro ↔ inodekey(ino) ∈ ri ∧ fs[ri[inodekey(ino)]].nlink = 0 ∧ ino ≠ ROOT_INO ⊦ # links(m, abs-dirs(fs, ri)) = 0, # ro = 0, fs[ri[inodekey(m)]].nlink = 0, ro = ∅

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 12 terms: m

Additional information

Used terms: m