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Proof step 22 from proof valid-parent-ino-precond (previous step)

fs[ri[inodekey(ROOT_INO)]].directory, ro.inodes?, fo.inodes?, afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), log-cons(log, fs), replay-cons-strong(fs, ri, ro, fi, fo, log), ri-inj(ri), ri-inj(fi), ubifs-cons(fs, ri, ro, fi, fo, log), inodekey(ROOT_INO) ∈ ri, inodekey(ROOT_INO) ∈ ro, ∀ ino. ino ∈ abs-keys(ro) ↔ ino ∈ abs-keys(orphans(fs, ri)) ⊦ # ro = 0, ro = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
fs[ri[inodekey(ROOT_INO)]].directory, fo.inodes?, ro.inodes?, afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), log-cons(log, fs), replay-cons-strong(fs, ri, ro, fi, fo, log), ri-inj(fi), ri-inj(ri), ubifs-cons(fs, ri, ro, fi, fo, log), inodekey(ROOT_INO) ∈ ro, inodekey(ROOT_INO) ∈ ri, ∀ ino. inodekey(ino) ∈ ro ↔ inodekey(ino) ∈ ri ∧ fs[ri[inodekey(ino)]].nlink = 0 ∧ ino ≠ ROOT_INO ⊦ # ro = 0, ro = ∅

Rule argument

Additional information

Used simplifier rules: ⊦ inodekey(m).ino = m; (s)% ⊦ inodekey(m).inode?; (s)%⊦ key ∈ orphans(fs, ri) ↔ key.inode? ∧ key ∈ ri ∧ fs[ri[key]].nlink = 0 ∧ key.ino ≠ ROOT_INO; (s)% ⊦ n ∈ abs-keys(ks) ↔ inodekey(n) ∈ ks; (s)