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Proof step 3 from proof valid-parent-ino-precond (previous step)

abs-keys(ro) = abs-keys(orphans(fs, ri)), fs[ri[inodekey(m)]].directory, ro.inodes?, fo.inodes?, afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), log-cons(log, fs), replay-cons-strong(fs, ri, ro, fi, fo, log), ri-inj(ri), ri-inj(fi), ubifs-cons(fs, ri, ro, fi, fo, log), inodekey(m) ∈ ri, links(m, abs-dirs(fs, ri)) ≠ ∅ ∨ m = ROOT_INO ⊦ (fs[ri[inodekey(m)]].nlink ≠ 0 ∨ m = ROOT_INO) ∧ ¬ inodekey(m) ∈ ro

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

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