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Proof step 20 from proof repalyone-monotonic (previous step)

datanode(key0, buf) = fs[adr], key ∈ (inodekey(key0.ino) ∈ ri0 ⊃ ri0[key0, adr];ri0), ∀ key. key ∈ ri0 → key ∈ ri1 ⊦ inodekey(key0.ino) ∈ ri1, key ∈ ri1, key ∈ ri0

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 21:
datanode(key0, buf) = fs[adr], key ∈ ri0[key0, adr], inodekey(key0.ino) ∈ ri0, ∀ key. key ∈ ri0 → key ∈ ri1 ⊦ key ∈ ri0, key ∈ ri1, inodekey(key0.ino) ∈ ri1

Rule argument

pos: left 2

Proof step 20 from proof repalyone-monotonic (previous step)

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

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