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Proof step 5 from proof replay-log-drop (previous step)

∀ fs, adr, ri. replay-log(log0, fs -- adr, ri) = replay-log(log0, fs, ri) ∨ adr ∈ log0 ⊦ adr = adr0, replay-log(log0, fs -- adr, replay-one(adr0, fs[adr0], ri)) = replay-log(log0, fs, replay-one(adr0, fs[adr0], ri)), adr ∈ log0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: fs, adr, replay-one(adr0, fs[adr0], ri)

Additional information

Used terms: fs, adr, replay-one(adr0, fs[adr0], ri)