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Proof step 46 from proof replay-one-update (previous step)

fs[ri[dentrykey(ino, str)]] = dentrynode(dentrykey(ino, str), m), m = 0, fs[ri[inodekey(ino)]].directory, ro.inodes?, orphans-cons(fs, ri, ro), inodekey(m) ∈ ri, inodekey(ino) ∈ ri, dentrykey(ino, str) ∈ ri, ri[dentrykey(ino, str)] ∈ fs, ∀ key. key ∈ ri → ri[key] ∈ fs ∧ key-cons(key, fs[ri[key]]) ⊦ (ri ⊖ ro) -- dentrykey(ino, str) = ri[dentrykey(ino, str), adr] ⊖ ro, inodekey(ino) ∈ ro, inodekey(m) ∈ ro

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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