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Proof step 21 from proof replay-orphans-trunc (previous step)

key ∈ ro ⊦ # ro = 0, key0 ∈ (ri \ datakeys(key, n, ri)) ⊖ ro ↔ key0 ∈ ri ⊖ ro, ro = ∅, (key0 ∈ (ri \ datakeys(key, n, ri)) ⊖ ro ↔ key0 ∈ ri ⊖ ro) ∧ (key0 ∈ (ri \ datakeys(key, n, ri)) ⊖ ro → ((ri \ datakeys(key, n, ri)) ⊖ ro)[key0] = (ri ⊖ ro)[key0])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
key ∈ ro ⊦ # ro = 0, key0 ∈ (ri \ datakeys(key, n, ri)) ⊖ ro ↔ key0 ∈ ri ⊖ ro, ro = ∅

Proof step 21 from proof replay-orphans-trunc (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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