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Proof step 7 from proof replay-safe-drop (previous step)

node-cons(fs[adr0].key, fs[adr0]), replay-safe(log0, fs -- adr, replay-one(adr0, fs[adr0], ri)), adr0 ∈ fs, ∀ fs, adr, ri. (replay-safe(log0, fs -- adr, ri) ↔ replay-safe(log0, fs, ri)) ∨ adr ∈ log0 ⊦ adr = adr0, replay-safe(log0, fs, replay-one(adr0, fs[adr0], ri)), adr0 ∈ ri, adr ∈ log0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: fs, adr, replay-one(adr0, fs[adr0], ri)

Additional information

Used terms: fs, adr, replay-one(adr0, fs[adr0], ri)