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Proof step 3 from proof replay-safe-split (previous step)

node-cons(fs[adr].key, fs[adr]), adr ∈ fs, ∀ log1, fs, ri. replay-safe(log + log1, fs, ri) ↔ replay-safe(log, fs, ri) ∧ replay-safe(log1, fs, replay-log(log, fs, ri)) ⊦ replay-safe(log + log1, fs, replay-one(adr, fs[adr], ri)) ↔ replay-safe(log, fs, replay-one(adr, fs[adr], ri)) ∧ replay-safe(log1, fs, replay-log(log, fs, replay-one(adr, fs[adr], ri))), adr ∈ ri

User applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: log1, fs, replay-one(adr, fs[adr], ri) abort: F discard: T computed: T

Additional information

Used terms: log1, fs, replay-one(adr, fs[adr], ri)