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Proof step 5 from proof replaylog-keep-adr (previous step)

adr ∈ replay-log(log0, fs, replay-one(adr0, fs[adr0], ri)), ∀ adr, fs, ri. adr ∈ replay-log(log0, fs, ri) → adr ∈ log0 ∨ adr ∈ ri ⊦ adr = adr0, adr ∈ ri, adr ∈ log0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: adr, fs, replay-one(adr0, fs[adr0], ri)

Additional information

Used simplifier rules: replayone-keep-adr: ⊦ adr0 ∈ replay-one(adr, nd, ri) ∧ adr0 ≠ adr → adr0 ∈ ri; Used terms: adr, fs, replay-one(adr0, fs[adr0], ri)