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Proof step 7 from proof replayone-keep-adr (previous step)

adr0 ∈ (boolvar ⊃ ri -- key;ri ⊖ key) ⊦ key.ino = ROOT_INO, adr0 = adr, adr0 ∈ ri

Heuristic if-then-else split applied rule case distinction

And closed the goal!

Rule argument

pos: left 1

Additional information

Used simplifier rules: ⊦ ¬ adr ∈ ri → ¬ adr ∈ ri ⊖ key; (s)% ⊦ ¬ adr ∈ ri → ¬ adr ∈ ri -- key; (s)